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0=1.7+10t-5t^2
We move all terms to the left:
0-(1.7+10t-5t^2)=0
We add all the numbers together, and all the variables
-(1.7+10t-5t^2)=0
We get rid of parentheses
5t^2-10t-1.7=0
a = 5; b = -10; c = -1.7;
Δ = b2-4ac
Δ = -102-4·5·(-1.7)
Δ = 134
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-\sqrt{134}}{2*5}=\frac{10-\sqrt{134}}{10} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+\sqrt{134}}{2*5}=\frac{10+\sqrt{134}}{10} $
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